3x+3y+3z=y^3

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Solution for 3x+3y+3z=y^3 equation:


Simplifying
3x + 3y + 3z = y3

Solving
3x + 3y + 3z = y3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3y' to each side of the equation.
3x + 3y + -3y + 3z = -3y + y3

Combine like terms: 3y + -3y = 0
3x + 0 + 3z = -3y + y3
3x + 3z = -3y + y3

Add '-3z' to each side of the equation.
3x + 3z + -3z = -3y + y3 + -3z

Combine like terms: 3z + -3z = 0
3x + 0 = -3y + y3 + -3z
3x = -3y + y3 + -3z

Divide each side by '3'.
x = -1y + 0.3333333333y3 + -1z

Simplifying
x = -1y + 0.3333333333y3 + -1z

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